Optimal. Leaf size=194 \[ \frac{(b c-a d) (5 a d+3 b c) \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt [4]{a+b x}}{\sqrt [4]{a} \sqrt [4]{c+d x}}\right )}{16 a^{7/4} c^{9/4}}+\frac{(b c-a d) (5 a d+3 b c) \tanh ^{-1}\left (\frac{\sqrt [4]{c} \sqrt [4]{a+b x}}{\sqrt [4]{a} \sqrt [4]{c+d x}}\right )}{16 a^{7/4} c^{9/4}}+\frac{\sqrt [4]{a+b x} (c+d x)^{3/4} (5 a d+3 b c)}{8 a c^2 x}-\frac{(a+b x)^{5/4} (c+d x)^{3/4}}{2 a c x^2} \]
[Out]
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Rubi [A] time = 0.309189, antiderivative size = 194, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273 \[ \frac{(b c-a d) (5 a d+3 b c) \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt [4]{a+b x}}{\sqrt [4]{a} \sqrt [4]{c+d x}}\right )}{16 a^{7/4} c^{9/4}}+\frac{(b c-a d) (5 a d+3 b c) \tanh ^{-1}\left (\frac{\sqrt [4]{c} \sqrt [4]{a+b x}}{\sqrt [4]{a} \sqrt [4]{c+d x}}\right )}{16 a^{7/4} c^{9/4}}+\frac{\sqrt [4]{a+b x} (c+d x)^{3/4} (5 a d+3 b c)}{8 a c^2 x}-\frac{(a+b x)^{5/4} (c+d x)^{3/4}}{2 a c x^2} \]
Antiderivative was successfully verified.
[In] Int[(a + b*x)^(1/4)/(x^3*(c + d*x)^(1/4)),x]
[Out]
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Rubi in Sympy [A] time = 27.8204, size = 175, normalized size = 0.9 \[ - \frac{\left (a + b x\right )^{\frac{5}{4}} \left (c + d x\right )^{\frac{3}{4}}}{2 a c x^{2}} + \frac{\sqrt [4]{a + b x} \left (c + d x\right )^{\frac{3}{4}} \left (5 a d + 3 b c\right )}{8 a c^{2} x} - \frac{\left (a d - b c\right ) \left (5 a d + 3 b c\right ) \operatorname{atan}{\left (\frac{\sqrt [4]{c} \sqrt [4]{a + b x}}{\sqrt [4]{a} \sqrt [4]{c + d x}} \right )}}{16 a^{\frac{7}{4}} c^{\frac{9}{4}}} - \frac{\left (a d - b c\right ) \left (5 a d + 3 b c\right ) \operatorname{atanh}{\left (\frac{\sqrt [4]{c} \sqrt [4]{a + b x}}{\sqrt [4]{a} \sqrt [4]{c + d x}} \right )}}{16 a^{\frac{7}{4}} c^{\frac{9}{4}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)**(1/4)/x**3/(d*x+c)**(1/4),x)
[Out]
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Mathematica [C] time = 0.39033, size = 211, normalized size = 1.09 \[ \frac{\frac{2 b d x^3 \left (5 a^2 d^2-2 a b c d-3 b^2 c^2\right ) F_1\left (1;\frac{3}{4},\frac{1}{4};2;-\frac{a}{b x},-\frac{c}{d x}\right )}{-8 b d x F_1\left (1;\frac{3}{4},\frac{1}{4};2;-\frac{a}{b x},-\frac{c}{d x}\right )+b c F_1\left (2;\frac{3}{4},\frac{5}{4};3;-\frac{a}{b x},-\frac{c}{d x}\right )+3 a d F_1\left (2;\frac{7}{4},\frac{1}{4};3;-\frac{a}{b x},-\frac{c}{d x}\right )}+(a+b x) (c+d x) (-4 a c+5 a d x-b c x)}{8 a c^2 x^2 (a+b x)^{3/4} \sqrt [4]{c+d x}} \]
Warning: Unable to verify antiderivative.
[In] Integrate[(a + b*x)^(1/4)/(x^3*(c + d*x)^(1/4)),x]
[Out]
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Maple [F] time = 0.052, size = 0, normalized size = 0. \[ \int{\frac{1}{{x}^{3}}\sqrt [4]{bx+a}{\frac{1}{\sqrt [4]{dx+c}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)^(1/4)/x^3/(d*x+c)^(1/4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (b x + a\right )}^{\frac{1}{4}}}{{\left (d x + c\right )}^{\frac{1}{4}} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(1/4)/((d*x + c)^(1/4)*x^3),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.278792, size = 1592, normalized size = 8.21 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(1/4)/((d*x + c)^(1/4)*x^3),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\sqrt [4]{a + b x}}{x^{3} \sqrt [4]{c + d x}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)**(1/4)/x**3/(d*x+c)**(1/4),x)
[Out]
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GIAC/XCAS [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(1/4)/((d*x + c)^(1/4)*x^3),x, algorithm="giac")
[Out]